t^2-4t+22=

Solution for t^2-4t+22= equation:

Simplifying
t2 + -4t + 22 = 0

Reorder the terms:
22 + -4t + t2 = 0

Solving
22 + -4t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-22' to each side of the equation.
22 + -4t + -22 + t2 = 0 + -22

Reorder the terms:
22 + -22 + -4t + t2 = 0 + -22

Combine like terms: 22 + -22 = 0
0 + -4t + t2 = 0 + -22
-4t + t2 = 0 + -22

Combine like terms: 0 + -22 = -22
-4t + t2 = -22

The t term is -4t.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4t + 4 + t2 = -22 + 4

Reorder the terms:
4 + -4t + t2 = -22 + 4

Combine like terms: -22 + 4 = -18
4 + -4t + t2 = -18

Factor a perfect square on the left side:
(t + -2)(t + -2) = -18

Can't calculate square root of the right side.

The solution to this equation could not be determined.